3b-8b = -5
8a-3b = 5
3b2 + b - 10 = 0 This quadratic equation can be factored. (3b -5)(b +2) = 0 The equation can be solved when either (3b - 5) = 0, or (b + 2) = 0. If 3b - 5 = 0 then 3b = 5 : b = 5/3 If b + 2 = 0 then b = -2 The roots or solutions to this equation are b = 5/3 and b = -2
6b^2 - 3b / 3b 6b^2 - 1 or ( 6b^2 - 3b) / 3b = 2b - 1 Or (6b^2 - 3b ) / 3b = 3b(2b - ) / 3b = 2b - 1
there is a sign missing -- if 4b +15 = 7b then 3b = 15 and b thus = 5 if 4b - 15 = 7b then 3b = -15 and b = -5
3b-8b = -5
8a-3b = 5
5 + 10ac + 3b
-2b + 7 -3b = 2 -2b +7 -3b +2b = 2 + 2b 7 -3b + 3b = 2 + 2b +3b 7-2 = 2-2 + 2b + 3b 5 = 5b 1 = b
5b plus 5-3b-7 is 2b-2.
50 - 3b = 353b = 50 - 353b = 15b = 5
if you meant to write the problem as "3b + 5 = 29", then this is how to solve: 3b + 5 = 29 - 5 - 5 subtract 5 from each side 3b = 24 simplify b = 8 divide each side by 3 to get b by itself
If b = 5 then 15-10 = 5
5
3b - 3 - 4b = 5Combine the 3b and the -4b :-1b - 3 = 5 Add 3 to each side of the equation:-1b = 8 Multiply each side by -1 : b = -8
3b2 + b - 10 = 0 This quadratic equation can be factored. (3b -5)(b +2) = 0 The equation can be solved when either (3b - 5) = 0, or (b + 2) = 0. If 3b - 5 = 0 then 3b = 5 : b = 5/3 If b + 2 = 0 then b = -2 The roots or solutions to this equation are b = 5/3 and b = -2
The equation cannot be solved as there are two unknowns. However it can be simplified and the two unknowns (a and b) expressed in terms of the second unknown. 1) Expressing a in terms of b 4a + 2 = 3b - 5 4a = 3b -7 if desired this could be stated as a = (3b - 7)/4 2) Expressing b in terms of a 3b - 5 = 4a + 2 3b = 4a + 7 if desired this could be stated as b = (4a + 7)/3