500 +
680 +
031
-------
1,211
2*100 + 31*10 + 27*1 = 200 + 310 + 27 = 537
31
Let the number of hundreds be represented as ( h ). According to the problem, the number has 3 hundreds more tens than hundreds, which gives us ( t = h + 3 ) for tens. It also states there is 1 more one than hundreds, leading to ( o = h + 1 ) for ones. Therefore, the number can be expressed as ( 100h + 10(h + 3) + (h + 1) = 111h + 31 ). For example, if ( h = 0 ), the number would be 31; if ( h = 1 ), it would be 142, and so on.
31, 53, 97
276
23971
2*100 + 31*10 + 27*1 = 200 + 310 + 27 = 537
31
Let the number of hundreds be represented as ( h ). According to the problem, the number has 3 hundreds more tens than hundreds, which gives us ( t = h + 3 ) for tens. It also states there is 1 more one than hundreds, leading to ( o = h + 1 ) for ones. Therefore, the number can be expressed as ( 100h + 10(h + 3) + (h + 1) = 111h + 31 ). For example, if ( h = 0 ), the number would be 31; if ( h = 1 ), it would be 142, and so on.
31, 53, 97
31
31 tens(310)
4 tens = 40.00 31 thousandths = 31/1000 = 0.031 4 tens 31 thousandths = 40+0.031 = 40.031 (in Decimals) 4 tens 31 thousandths = 40031/1000 ( in fraction)
276
20, 31, 42, 53, 64, 75, 86, 97
ud
To the nearest hundredths place 30.9199 is rounded off to 30.92. To the nearest tenth place 30.9199 is rounded off to 30.9. To the nearest ones 30.9199 is rounded off to 31. To the nearest tens 30.9199 is rounded off to 30. To the nearest hundreds 30.9199 is rounded off to 0.