If I am getting what you are saying, then no. 3 rows of 9 and 2 rows equals 5 rows. 5*9=45 and 7*9=63
1 row of 180 - 2 rows of 90 - 3 rows of 60 - 4 rows of 45 - 5 rows of 36 - 6 rows of 30 - 9 rows of 20 - 10 rows of 18 - 12 rows of 15 - 15 rows of 12 - 18 rows of 10 - 20 rows of 9 - 30 rows of 6 - 36 rows of 5 - 45 rows of 4 - 60 rows of 3 - 90 rows of 2 - 180 rows of 1 - total of 18 ways within the limits of the question
Six ways. 15 rows of 2 trees 6 rows of 5 trees 3 rows of 10 trees and 2 rows of 15 trees 5 rows of 6 trees 10 rows of 3 trees * * * * * How about 1 row of 30 trees and 30 rows of 1 tree each?
Draw either 3 rows of 5 columns or 5 rows of 3 columns.
Two ways only. 4 rows with 25 stamps each or 5 rows with 20 stamps each.
33 desks can be arranged into six rows having no rows, 1 row, 2 rows, 3 rows, 4 rows, or 5 rows with exactly 5 desks.
If I am getting what you are saying, then no. 3 rows of 9 and 2 rows equals 5 rows. 5*9=45 and 7*9=63
by 2 rows
1 row of 180 - 2 rows of 90 - 3 rows of 60 - 4 rows of 45 - 5 rows of 36 - 6 rows of 30 - 9 rows of 20 - 10 rows of 18 - 12 rows of 15 - 15 rows of 12 - 18 rows of 10 - 20 rows of 9 - 30 rows of 6 - 36 rows of 5 - 45 rows of 4 - 60 rows of 3 - 90 rows of 2 - 180 rows of 1 - total of 18 ways within the limits of the question
Six ways. 15 rows of 2 trees 6 rows of 5 trees 3 rows of 10 trees and 2 rows of 15 trees 5 rows of 6 trees 10 rows of 3 trees * * * * * How about 1 row of 30 trees and 30 rows of 1 tree each?
1 row of 100 chairs. 2 rows of 50 chairs. 4 rows of 25 chairs. 5 rows of 20 chairs. 10 rows of 10 chairs. 20 rows of 5 chairs. 25 rows of 4 chairs. 50 rows of 2 chairs. 100 rows of 1 chair. Or you could put them all in one big circle.
Having the same number of students in each row, 80 students can be arranged in 80 rows of 1, 40 rows of 2, 20 rows of 4, 10 rows of 8, and 5 rows of 16.
You can have: 1 row of 36 2 rows of 18 3 rows of 12 4 rows of 9 or 6 rows of 6, so in total there are 5 ways.
Full outer join will fetch at maximum 'addition of 2 tables' Ex: Table A - 2 rows; Table B - 3 rows. Full outer join will fetch in 2+3 = 5 rows. Where as in Cartesian product will fetch in 'product of 2 tables'. Ex: Table A - 2 rows; Table B - 3 rows. Full outer join will fetch in 2x3 = 6 rows
Draw either 3 rows of 5 columns or 5 rows of 3 columns.
Sparky had room for 16 rows in his garden He planted 3 rows of tomatoes for every 5 rows of onions He planted 10 rows of onions.
Sparky had room for 16 rows in his garden He planted 3 rows of tomatoes for every 5 rows of onions. 6 rows of tomatoes were planted.