5 times 13 times 2 =
2 times 5 times 13 =
10 times 13 =
130
2 times 2 times 5 times 5 times 11 times 13.
To express (\log_{13}(145)) using (\log_{13}(2)), (\log_{13}(3)), and (\log_{13}(5)), first factor 145 into its prime components: (145 = 5 \times 29). Then, use the logarithmic property that states (\log_b(mn) = \log_b(m) + \log_b(n)). Since 29 can be expressed as (2 \times 3 \times 5), we have (\log_{13}(145) = \log_{13}(5) + \log_{13}(29)) and can derive (\log_{13}(29)) from the logs of 2 and 3 using their product.
I am guessing your problem is to compute 5 times 2 times 13. In this case, the property you are using the associative property.
It is: 13/2 times 2 = 13
The 13 times tables are as follows: 1 times 13 is 13, 2 times 13 is 26, 3 times 13 is 39, 4 times 13 is 52, 5 times 13 is 65, 6 times 13 is 78, 7 times 13 is 91, 8 times 13 is 104, 9 times 13 is 117, 10 times 13 is 130, 11 times 13 is 143, and 12 times 13 is 156.
2 times 2 times 5 times 5 times 11 times 13.
13x2x5=130
5 + (2 x 4) = 13
2 5/8 x 5 is 13 1/8.
4/5 of 2 is 1 3/5
2.7692 times.
13/1 multiplied by 1/5 is 2 3/5
To express (\log_{13}(145)) using (\log_{13}(2)), (\log_{13}(3)), and (\log_{13}(5)), first factor 145 into its prime components: (145 = 5 \times 29). Then, use the logarithmic property that states (\log_b(mn) = \log_b(m) + \log_b(n)). Since 29 can be expressed as (2 \times 3 \times 5), we have (\log_{13}(145) = \log_{13}(5) + \log_{13}(29)) and can derive (\log_{13}(29)) from the logs of 2 and 3 using their product.
if the number is the same: 2x + 3x = 13 5x = 13 x= 13/5
I am guessing your problem is to compute 5 times 2 times 13. In this case, the property you are using the associative property.
it goes into it 2.6 times learn division
It is: 13/2 times 2 = 13