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What is the volume of a rectangular prism with length 6 yd width 5 yd and height 3 yd?
To find the volume of a rectangular prism, you multiply (length)(width)(height). In this case, you multiply 6 times 5 times 3, and your answer is 180.
6 yards 5 inches minus 2 yards 7 inches?
1 yd = 36 in 6 yd 5 in - 2 yd 7 in = (5 + 1) yd 5 in - 2 yd 7 in = 5 yd (36 + 5) in - 2 yd 7 in = (5-2) yd (36 + 5 - 7) in = 3 yd 34 in.
What part of a yard is five twelfths of a foot?
3ft = 1 yd 1 ft = 1/3 yd 5/12 ft = 5/12 x 1/3 yd = 5/36 yd.
What is 5 yd 1 ft minus 3 yd 2 ft?
2 yd 2 ft
How many cubic yards of concrete do you need for a slab 4800 sq ft 5 in thick?
1 yd = 3 ft → 1 sq yd = 1 yd x 1 yd = 3 ft x 3 ft = 9 ft 1 yd = 36 in → volume = 4800 sq ft x 5 in = 4800 ÷ 9 sq yd x 5 ÷ 36 yd = 74 2/27 cu yd ≈ 74.074 cu yd.
What is the volume of a rectangular prism with length 6 yd width 5 yd and height 3 yd?
To find the volume of a rectangular prism, you multiply (length)(width)(height). In this case, you multiply 6 times 5 times 3, and your answer is 180.
How many feet are in 5yd?
There are 3 ft. in 1 yd., so 3 times 5=15ft.
What is the surface area for 5 yd by 3 yd by 9 yd?
174 sq. yards
6 yards 5 inches minus 2 yards 7 inches?
1 yd = 36 in 6 yd 5 in - 2 yd 7 in = (5 + 1) yd 5 in - 2 yd 7 in = 5 yd (36 + 5) in - 2 yd 7 in = (5-2) yd (36 + 5 - 7) in = 3 yd 34 in.
What part of a yard is five twelfths of a foot?
3ft = 1 yd 1 ft = 1/3 yd 5/12 ft = 5/12 x 1/3 yd = 5/36 yd.
What is bigger 5yd or 5ft?
5 yd. 1 yd = 3 ft
What is the perimeter of a rectangle that is 5 yd long and 3 yd wide?
16yd
How many times do 5ft go into 36yd?
36 yd / 5 ft = 36*3 ft / 5 ft = 108/5 = 21.6
What is 5 yd 1 ft minus 3 yd 2 ft?
2 yd 2 ft
How many cubic yards of concrete do you need for a slab 4800 sq ft 5 in thick?
1 yd = 3 ft → 1 sq yd = 1 yd x 1 yd = 3 ft x 3 ft = 9 ft 1 yd = 36 in → volume = 4800 sq ft x 5 in = 4800 ÷ 9 sq yd x 5 ÷ 36 yd = 74 2/27 cu yd ≈ 74.074 cu yd.
The length of a rectangle is three times its width If the area of the rectangle is 75yd2 find its perimeter?
Given that L x W = 75 yd2 and L = 3W. Substituting 3W for L, 3W x 1W = 3 W2 = 75 yd2 Dividing each side by 3, W2 = 25 yd2 Taking the square root of each side, W = 5 yd so L = 3 x 5 yd = 15 yd Perimeter = 2 x (L + W) = 2 x (15 yd + 5 yd) = 2 x 20 yd = 40 yd
What is the surface area for a base of 5 yd a height of 9 yd nd a width of 3 yd?
174 sq. yds
