3h + (2h 20m) + 35m = (3+2)h + (20+35)m = 5h + 55m
5h - 3h + 9h = 176 11h = 176 h = 16
h=16
The simplified expression of 10h+6-5h+3 is 5h+9
Sample Space is: 1H, 2H, 3H, 4H, 5H, 6H, 1T, 2T, 3T, 4T, 5T, 6T (where H = Heads & T = Tails).
3h-5h + 11 = 17 is ------2h + 11 = 17- 11 -11____________-2h = 6___ ___-2 -2h = -3 (This is the answer.)
8h - 10h = 3h + 25-2h = 3h + 25-5h = 25-h = 5h = -5
3h + (2h 20m) + 35m = (3+2)h + (20+35)m = 5h + 55m
h = -5 8h - 10h = 3h + 25 -2h = 3h + 25 -2h - 3h = 3h - 3h + 25 -5h = 25 h = -5 CHECK: 8(-5) - 10(-5) = 3(-5) + 25 -40 - -50 = -15 + 25 -40 + 50 = 10 10 = 10 CORRECT
5h - 3h + 9h = 176 11h = 176 h = 16
h = 0.538462 14 + 5h + 2h = 5h + 28h 14 + 7h = 33h 14 + 7h - 7h = 33h - 7h 14 = 26h 14/26 = 26/26h 0..538462 = h
h=16
The simplified expression of 10h+6-5h+3 is 5h+9
6h+4g
Sample Space is: 1H, 2H, 3H, 4H, 5H, 6H, 1T, 2T, 3T, 4T, 5T, 6T (where H = Heads & T = Tails).
If you mean: 10h+6-5h+3 then it is 5h+9 when simplified
Protium (1H), Deuterium (2H), and Tritium (3H) are the three isotopes of hydrogen.Only the first two occur naturally, the third can only be produced in nuclear reactors or nuclear bombs typically from lithium.* Hydrogen (1H)* Deuterium (2H or D)* Tritium (3H or T)* 4H* 5H* 6H* 7HHydrogen, deuterium and tritium atre natural isotopes; isotopes 3H-7H are radioactive and unstables.