Let the number is x So, X+20=69 X=69-20 X=49 THE NUMBER IS 49 SO, 49 plus 20 equal to 69 .•.
x+27=43 x+27-27=43-27 x+0=16
76= -43 + X add 43 to both sides 76 + 43 = -43 + 43 + x 119 = x
2x + 15 = 8x + 43 -6x = 28 x = -6 / 28 = -3 / 14
4x + 69 = 30 + 5xSeparate the variables and constants (subtract 4x from each side):69 = 30 + xSubtract 30 from each side (your variable is already a unit) :39 = x
Let the number is x So, X+20=69 X=69-20 X=49 THE NUMBER IS 49 SO, 49 plus 20 equal to 69 .•.
x+27=43 x+27-27=43-27 x+0=16
x=7
x=12
76= -43 + X add 43 to both sides 76 + 43 = -43 + 43 + x 119 = x
2x + 15 = 8x + 43 -6x = 28 x = -6 / 28 = -3 / 14
x = 13 x 12 + 1 = 43 x 1 + 1 = 43 + 1 = 44 = 4
I x=5 and y=2, then (5x5)=25 plus (9x2)=18. 25+18=43
896 + (7865 x 6749) - (5748 x 69) = 52,685,169
(6 x 9) + 6 + 9 = 69
This is the existence of additive inverse: For every number, x, there exists a number, denoted by (-x), such that x + (-x) = (-x) + x = 0.
1 x 43, 43 x 1.