62 = (6 x 10) + (2 x 1)
6.2 x 10 = 62
6x + 10 = 72 6x = 72 - 10 x = 62/6 x = 10.3333
62, L=50, X=10, I=1, I=1 50+10= 60 60+ 1+1= 62
1 x 62, 2 x 31, 31 x 2, 62 x 1 = 62
62 tens is the same as 62 x 10: 62 x 10 = 620
-9x - 10 = 62 -9x = 72 x = -8
The first ten positive integer multiples of 62 are: 1 x 62 = 62 2 x 62 = 124 3 x 62 = 186 4 x 62 = 248 5 x 62 = 310 6 x 62 = 372 7 x 62 = 434 8 x 62 = 496 9 x 62 = 558 10 x 62 = 620
62 = (6 x 10) + (2 x 1)
6.2 x 10 = 62
It is 62 x 5 = 310
To find two numbers that multiply to 310, we can start by finding the prime factorization of 310, which is 2 x 5 x 31. From this, we can see that 310 can be expressed as 2 x 5 x 31. Therefore, the two numbers that multiply to 310 are 2 and 155, or 5 and 62, or 10 and 31.
if x= -62 then -x= 62
6x + 10 = 72 6x = 72 - 10 x = 62/6 x = 10.3333
62 of them
62, L=50, X=10, I=1, I=1 50+10= 60 60+ 1+1= 62
1 x 62, 2 x 31, 31 x 2, 62 x 1 = 62