3*21 = 63 so 63 is divisible by 3 7*9 = 63 so 63 is divisible by 7.
Yes they are. They are both divisible by 7. 14/2= 7 and 63/9=7
7 x 9 = 63 7 is a FACTOR of 63 9 is a FACTOR of 63 7 and 9 are even DIVISORS of 63 63 is a MULTIPLE of 7 and 9 63 is a PRODUCT of 7 and 9 63 is evenly DIVISIBLE by 7 or 9
7 and 9 are factors and divisors of 63 63 is a multiple and a product of 7 and 9 63 is divisible by 7 and 9
No, it is divisible by 7 and 9 along with 1, and 63 which don't count.
3*21 = 63 so 63 is divisible by 3 7*9 = 63 so 63 is divisible by 7.
Yes they are. They are both divisible by 7. 14/2= 7 and 63/9=7
Yes beacause 9 times 7 is 63
Yes and the answer is 9 because 9*7 = 63
1, 3, 7, 9, 21, 63
7 and 9 are factors and divisors of 63. 63 is a multiple and product of 7 and 9. 63 is divisible by 7 and 9.
63
7 x 9 = 63 7 is a FACTOR of 63 9 is a FACTOR of 63 7 and 9 are even DIVISORS of 63 63 is a MULTIPLE of 7 and 9 63 is a PRODUCT of 7 and 9 63 is evenly DIVISIBLE by 7 or 9
7 and 9 are factors and divisors of 63 63 is a multiple and a product of 7 and 9 63 is divisible by 7 and 9
No, it is divisible by 7 and 9 along with 1, and 63 which don't count.
the factors of 63 are 3, 3 and 7. The natural numbers that can be multiplied to make 63 are : 1 * 63 3 * 21 9 * 7 7 * 9 21 * 3 63 * 1
45/63 45 ÷ 9 = 5 63 ÷ 9 = 7 so 45/63 = 5/7; 5 to 7; 5:7