64 times 1344 equals 86,016. This can be calculated by multiplying the two numbers directly. Therefore, 64 × 1344 = 86,016.
LCM of 64 and 42 is 1344.
448 x 3 = 1344 224 x 6 = 1344 And so on...
To find the partial products of 48 times 28, we can break down the numbers. We can express 48 as 40 + 8 and 28 as 20 + 8. Then, we calculate the partial products: 40 × 20 = 800 40 × 8 = 320 8 × 20 = 160 8 × 8 = 64 Adding these together gives 800 + 320 + 160 + 64 = 1344. Thus, the product of 48 and 28 is 1344.
Let the number 'm' & 'n' Hence # Multiplication mn = - 1344 Added m + n = 43 We have two unknowns , So we eliminate one of them . Hence mn = -1344 m = 43 - n Substitute (43 - n) n = -1344 43n - n^(2) = -1344 n^(2) - 43n - 1344 = 0 We now have quadratic eq;n to solve Hence n = { --43 +/- sqrt[(-43)^(2) - 4(1)(-1344)]} / 2(1) n = { 43 +-/ sqrt[ 1849 + 5376]} / 2 n = { 43 +/-sqrt[ 7225] } / 2 n = { 43 +/- 85}/2 n = 128/2 = 64 & n = - 42/2 = -21 Verification 64 X -21 = -1344 64 - 21 = 43 So the two numbers are '-21' & '64'.
First, find the factors:56 = 23*748 = 24*364 = 26Then, multiply the factors, only using like factors once:LCM = 26*3*7 = 1344
Least common multiple of 56 48 and 64 is 1344.
1344
LCM of 64 and 42 is 1344.
448 x 3 = 1344 224 x 6 = 1344 And so on...
32 * 42 = 1344Lining them up and multiplying each digit at a time yields 84 + 1260 = 1344, or 64 + 1280 = 1344.Also, splitting it into 7 and 6 (42), we can multiply it yielding 224 * 6 = 1344.
To find the partial products of 48 times 28, we can break down the numbers. We can express 48 as 40 + 8 and 28 as 20 + 8. Then, we calculate the partial products: 40 × 20 = 800 40 × 8 = 320 8 × 20 = 160 8 × 8 = 64 Adding these together gives 800 + 320 + 160 + 64 = 1344. Thus, the product of 48 and 28 is 1344.
No because the LCM of 42 and 64 is 1344
Let the number 'm' & 'n' Hence # Multiplication mn = - 1344 Added m + n = 43 We have two unknowns , So we eliminate one of them . Hence mn = -1344 m = 43 - n Substitute (43 - n) n = -1344 43n - n^(2) = -1344 n^(2) - 43n - 1344 = 0 We now have quadratic eq;n to solve Hence n = { --43 +/- sqrt[(-43)^(2) - 4(1)(-1344)]} / 2(1) n = { 43 +-/ sqrt[ 1849 + 5376]} / 2 n = { 43 +/-sqrt[ 7225] } / 2 n = { 43 +/- 85}/2 n = 128/2 = 64 & n = - 42/2 = -21 Verification 64 X -21 = -1344 64 - 21 = 43 So the two numbers are '-21' & '64'.
168 x 8 = 1344
14 x 96 = 1344
It is: 42*32 = 1344
The positive integer factors of 1344 are: 1, 2, 3, 4, 6, 7, 8, 12, 14, 16, 21, 24, 28, 32, 42, 48, 56, 64, 84, 96, 112, 168, 192, 224, 336, 448, 672, 1344