6/2(1+2)=? The answer is 9.
The BIDMAS or PEMDAS Rule says that brackets must be done first.
1) (1+2)=3
Then you do multiplication or division first since it is the next step in the rules that apply to this equation.
Many are confused as to which one they are supposed to do because they give a different answer. However, all equations are solved by left-to-right if you must choose from times and divide, or plus and minus.
2)6/2=3
Now the equation is: 3(3)
This means multiply.
3)3*3=9
The equation is solved.
4 + (2/32) + 1
x[x+1] squared Simplified is, to my knowledge, x squared plus ( x + 1) squared
Multiplication and division first, addition and subtraction second. Without brackets, that equation equals 2.
3(x + 1)(x + 3)
It does. Follow order of operations (BEDMAS): (2+10)/(2x6), brackets first (12)/(12), no exponents 12/12 = 1 by division
4 + (2/32) + 1
2(2n + 5) = 12 2n + 5 = 6 2n = 1 n = 1/2
x[x+1] squared Simplified is, to my knowledge, x squared plus ( x + 1) squared
6abc
Multiplication and division first, addition and subtraction second. Without brackets, that equation equals 2.
3(x + 1)(x + 3)
ANSWER:1+1= 2/1=2+1=3/1=3+1=4/1=4+1=5/1=5+1=6the answer is 6answer is 2.If you put parentheses after all your "divided by" 's and go on forever, this converges to the golden ratio.
It does. Follow order of operations (BEDMAS): (2+10)/(2x6), brackets first (12)/(12), no exponents 12/12 = 1 by division
There is some ambiguity in the question because of the absence of brackets. For example, is it 1/x + 3 ... or 1/(x+3) ... ? So, this is my interpretation of the question. If it is not what you meant please resubmit using brackets. 1/(x+3) + 1/1/(x-3) = 1/(x+3) + (x - 3) = (1 + x2 - 9)/(x + 3) = (x2 - 8)/(x + 3)
Brackets are used when you want a part of the sum to be done first...EX. 5 + (4+1) On this sum you do the 4 plus 1 first then you add it to five. Brackets separate the sum out! In any case because my example was very easy you do what is in the brackets first
In the absence of brackets, multiplication and division happen before addition and subtraction. (93 x 93) + (93/93) = 8649 + 1 = 8650
2/y + 1 + 3 + 5y