5 x 5 x 5 = 125 6 x 6 x 6 = 216 7 x 7 x 7 = 343
0 x 125 = 0 1 x 125 = 125 2 x 125 = 250 3 x 125 = 375 4 x 125 = 500 5 x 125 = 625 6 x 125 = 750 7 x 125 = 875 8 x 125 = 1000 9 x 125 = 1125 10 x 125 = 1250 11 x 125 = 1375 12 x 125 = 1500 et.seq.,
1 x 125, 5 x 25, 25 x 5, 125 x 1 = 125
x^3=125 x=5
1 x 125, 5 x 25 = 125
(125/N) = 6 6 x N = 125 N = 125/6 = 20 and 5/6
5 x 5 x 5 = 125 6 x 6 x 6 = 216 7 x 7 x 7 = 343
0 x 125 = 0 1 x 125 = 125 2 x 125 = 250 3 x 125 = 375 4 x 125 = 500 5 x 125 = 625 6 x 125 = 750 7 x 125 = 875 8 x 125 = 1000 9 x 125 = 1125 10 x 125 = 1250 11 x 125 = 1375 12 x 125 = 1500 et.seq.,
6 x 125 mm or 6 x 5 inch
20 with 5 remaining 125 - 5 = 120 = 6 x 20
1 x 125, 5 x 25 = 125
1 x 125, 5 x 25, 25 x 5, 125 x 1 = 125
The probability of 1 roll of 4 rolls of a die being 6 is: 1/6 x 5/6 x 5/6 x 5/6 = 125/1296 However, that one roll could be the first, second, third or fourth roll, so the total probability is 4 times this: Pr(one 6 on 4 rolls of 1 die) = 4 x 125/1296 = 125/324 ≈ 0.385
5/6 / 2/3 x 100 = 125 Therefore, 5/6 is 125 percent of 2/3.
x^3=125 x=5
125 = 1 x 125, 5 x 25
1 x 125, 5 x 25 = 125