-4/3
and
-3/2
To solve this, you must find the two factors that multiply to equal that trinomial (or use the quadratic equation)
that trinomial can be rewritten as
(3t + 4)(2t + 3) *check this first. It will prove that it is correct*
Then, find the values of t when the equation equals 0 and you will see that the solutions are
-4/3
and -3/2
6t2+17t+7 = (3t+7)(2t+1) when factored
For "6t - (2t2)", it is not reducible. For "(6t - 2t2)", it is 16t2
8t + 5 = 6t + 1,subtract 6t an 5 from each side,2t = -4t = -2Checking, 8t + 5 = -16 + 5 = -11 and 6t +1 = -12 + 1 = -11
6t+t = 7t
6t2+25+11 = (3t+11)(2t+1) when factored Use the quadratic equation formula.
6t2+17t+7 = (3t+7)(2t+1) when factored
Form the equation: 15-6t = 11t. Add 6t to both sides of the equation to obtain: 15 = 17t or 17t = 15. Divide both sides of the equation by 17 to obtain: t = 15/17.
For "6t - (2t2)", it is not reducible. For "(6t - 2t2)", it is 16t2
8t + 5 = 6t + 1,subtract 6t an 5 from each side,2t = -4t = -2Checking, 8t + 5 = -16 + 5 = -11 and 6t +1 = -12 + 1 = -11
12
6t+t = 7t
9t2
3t2 + 5t + 6t + 2t2 - 6t - 4is the same thing as 5t2 + 5t - 4.But that's not an 'answer'. There's no question in the original expression.
6t2+25+11 = (3t+11)(2t+1) when factored Use the quadratic equation formula.
As an algebraic expression it is simply: 6t+5
6t -2t + 5u = 4t - 5u
6t 6(2) t=2 12 The answer is 12.