Average of three test scores is 84 can be written (x+y+z)/3=84. If you know two of the scores then (79+93+z)/3=84, so to solve for z, 79+93+z=84*3 z=252-79-93 z=80 The first test score was 80
2 x 2 x 2 x 3 = 24 2 x 2 x 3 x 7 = 84 2 x 2 x 2 x 3 x 7 = 168, the LCM
3/14 = x/84 Multiply by 84 on both sides: (3/14) x 84 = x x = (3 x 84)/14 = 18
5 x 79 = 395
79 x 86 = 6974
79% of 84 is the same as .79 x 84 If you need help with multiplication, you know where to ask.
84/2 = 42/2 = 21/3 = 7/7 = 1 2 x 2 x 3 x 7 = 84
Average of three test scores is 84 can be written (x+y+z)/3=84. If you know two of the scores then (79+93+z)/3=84, so to solve for z, 79+93+z=84*3 z=252-79-93 z=80 The first test score was 80
79
493,039
2 x 2 x 2 x 3 = 24 2 x 2 x 3 x 7 = 84 2 x 2 x 2 x 3 x 7 = 168, the LCM
Factor them. 2 x 2 x 2 x 2 x 3 = 48 2 x 2 x 3 x 7 = 84 Select the common factors. 2 x 2 x 3 = 12, the GCF
158 = x * 79 158 / 79 = x 2 = x 158 is 200% of 79 ■
x - 56 = 79 x - 56 + 56 = 79 + 56 x = 135
1 x 79
3/14 = x/84 Multiply by 84 on both sides: (3/14) x 84 = x x = (3 x 84)/14 = 18
79 x 3 = 237