1x1000+7x100+6x10+0x1
Write 567.23 as a sum ANSWER: 5x102 + 6x101 + 7x100 + 2x10-1 + 2x10-2
Write 567.23 as a sum ANSWER: 5x102 + 6x101 + 7x100 + 2x10-1 + 2x10-2
35727
7 meters.100cm are in 1 meter,so 7x100=700 cm,with 84 cm left.it only needs 26 more meters to be at 8 meters
1x1000+7x100+6x10+0x1
Write 567.23 as a sum ANSWER: 5x102 + 6x101 + 7x100 + 2x10-1 + 2x10-2
Write 567.23 as a sum ANSWER: 5x102 + 6x101 + 7x100 + 2x10-1 + 2x10-2
35727
784.3 =(7x100) + (8x10) + (4x1) + (3x1/10)700 + 80 + 4 + 3/10
62 704 =(6x10 000) + (2x1000) + (7x100) + (0x10) + (4x1)60 000 + 2000 + 700 + 0 + 4
80 788 =(8x10 000) + (0x1000) + (7x100) + (8x10) + (8x1)80 000 + 0 + 700 + 80 + 8
705 =700 + 0 + 57(100) + 0(10) + 5(1)(7x100) + (0x10) + (5x1)
7 meters =700 because 7x100=700 and 7 is equal to 700 centimeters.
703 =700 + 0 + 37(100) + 0(10) + 3(1)(7x100) + (0x10) + (3x1)Alternatively, you can leave out the placeholders (0, zeros)
7 meters.100cm are in 1 meter,so 7x100=700 cm,with 84 cm left.it only needs 26 more meters to be at 8 meters
1 = 100/100, therefore .75 is 75/100...... 7x100/100= 700/100. 700/100+75/100= 775/100.... make that into a smaller number and you'll have 31/5