3t - 1
-3t
6t2+17t+7 = (3t+7)(2t+1) when factored
R = S + 2T S = 3T .... substitute R = (3T) + 2T R = 5T
If that's + 7t, the answer is (3t + 5)(2t - 1) If that's - 7t, the answer is (3t - 5)(2t + 1)
3t + 7 = 2t - 5 3t = 2t - 12 t = -12
4
2t + 3 = -9Subtract 3 from each side:2t = -12Divide each side by 2:t = -6======================-3t - 7 = (-3)(-6) - 7 = +18 - 7= 11.
if you mean T-3t+2t+4 (T and t is different variables):T-3t+2t+4=T-t+4if you mean t-3t+2t+4:t-3t+2t+4=4
2t x 3t = 6t2
2t-5t=-3t
Okay, I am going to assume you have a basic knowledge of Algebra and just show you how to solve the problem, step by step.6t2 + 13t - 63(3t - 7)(2t + 9)Check:(3t)(2t) - (7)(2t) + (3t)(9) - (7)(9)6t2 - 14t + 27t - 636t2 + 13t - 63
3t - 1
7 +5t
-3t
6t2+17t+7 = (3t+7)(2t+1) when factored
In 2t+8 19