7 groups, with 3 in each3 groups, with 7 in each21 groups, with 1 in each1 group, with 21 in each
[1 3 2 7] [7 6] [6 3 4] [3 4 1 1 4] [1 4 8] [3 1 9] [9 2 2] 7
-7+3, or 3-7.
You can make three different groups of three out of nine. 9/3=3
7 + 7*3!/3 = 7 + 7*6/3 = 7 + 7*2 = 7 + 14 = 21
There are 7.
divide -- 22/3 - 7 groups of 3 with 1 left over
7 groups, with 3 in each3 groups, with 7 in each21 groups, with 1 in each1 group, with 21 in each
There are three possibilities:-- 7 equal groups, with 3 in each group-- 3 equal groups, with 7 in each group-- 21 equal groups, with 1 in each group
Yes. It can be divided into -- 21 equal groups of 1 each -- 3 equal groups of 7 each -- 7 equal groups of 3 each
To find out how many groups of 7 equals 21, you can divide 21 by 7. The result is 3, which means there are 3 groups of 7 in 21. This is because when you multiply 7 by 3, you get 21. So, there are 3 groups of 7 that equal 21.
3 equal groups of 7 or vice versa, if you mean groups of even nos-no
It depends partly on whether the question refers to "of abjkp" or "ofabjkp". Number of groups of 3 from 5: 10 Number of groups of 3 from 7: 35
7 of them.
42 because 24 divided by 7 = 6
If you count back or subtract the divisor from the dividend then you get the number of groups. For example12/3 can be done like12 is the dividend and 3 is the divisor.12 -3, 9-3, 6-3, 3-3 which will give us 4 groups.12/5 can be done like12-5, 7-5 (in this case you get 2 which will be considered as reminder) and 12-5, 7-5 are 2 groups.Hope this helps.
7 groups of 4000= 7 x 4000 7 x 4000 = 28 000