7 is to 34 as 5 is to
7 is to 34 (3+4=7) so perhaps 5 is to 32 (3+2=5)
32
13
17z + 34 = 6z + 5 17z - 6z + 34 = 6z - 6z + 5 11z + 34 = 5 11z + 34 - 34 = 5 - 34 11z = -29 11z/11 = -29/11 z = -2 7/11 or -29/11 Double check your answer: 17z + 34 = 6z + 5 17(-2 7/11) + 34 = 6z + 5 -44 9/11 + 34 = 6z + 5 -10 9/11 = 6z + 5 -10 9/11 = 6(-2 7/11) + 5 -10 9/11 = -15 9/11 + 5 -10 9/11 = -10 9/11 17z + 34 = 6z + 5 when Z = -2 7/11
To solve this analogy, we need to determine the relationship between 7 and 34, and then apply that same relationship to 5. In this case, 7 is 5 more than 2 (7-2=5), and 34 is 5 times 7 (7*5=35, but we need to subtract 1 to get 34). Therefore, we need to find a number that is 5 more than 2 and then multiply that number by 5 to find the missing value. The missing value is 5 times (5+2) which equals 35.
7 is to 34 (3+4=7) so perhaps 5 is to 32 (3+2=5)
43
32
13
Answer: 23. 3+4=7 2+3=5
The Answer is 41 3+4= 7 4+1= 5
7 is to 34 as 5 is to 41 7-3=4 as 5-4=1 Thats the most logical answer I could come up with
17z + 34 = 6z + 5 17z - 6z + 34 = 6z - 6z + 5 11z + 34 = 5 11z + 34 - 34 = 5 - 34 11z = -29 11z/11 = -29/11 z = -2 7/11 or -29/11 Double check your answer: 17z + 34 = 6z + 5 17(-2 7/11) + 34 = 6z + 5 -44 9/11 + 34 = 6z + 5 -10 9/11 = 6z + 5 -10 9/11 = 6(-2 7/11) + 5 -10 9/11 = -15 9/11 + 5 -10 9/11 = -10 9/11 17z + 34 = 6z + 5 when Z = -2 7/11
32
32
34