2 x 7 x 7
7 times 7 times 2 is equal to 98.
The expression (2^7) represents 2 raised to the power of 7. This can be calculated as (2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2), which equals 128. Therefore, (2^7 = 128).
2 to the power 6 times 7.
To express (2^{-5} \times 28) as an exponential expression, we can first rewrite 28 in terms of base 2. Since (28 = 4 \times 7 = 2^2 \times 7), we can substitute this into the expression: [ 2^{-5} \times 28 = 2^{-5} \times (2^2 \times 7) = 2^{-5 + 2} \times 7 = 2^{-3} \times 7. ] Thus, the exponential expression is (2^{-3} \times 7).
7 times 2 times 3 is equal to 42.
7 times 7 times 2 is equal to 98.
well... order of operations... says 7 + (2x3) - (5x2) which is 7 + 6 - 10 simplified as 13 - 10
The expression (2^7) represents 2 raised to the power of 7. This can be calculated as (2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2), which equals 128. Therefore, (2^7 = 128).
2 to the power 6 times 7.
To express (2^{-5} \times 28) as an exponential expression, we can first rewrite 28 in terms of base 2. Since (28 = 4 \times 7 = 2^2 \times 7), we can substitute this into the expression: [ 2^{-5} \times 28 = 2^{-5} \times (2^2 \times 7) = 2^{-5 + 2} \times 7 = 2^{-3} \times 7. ] Thus, the exponential expression is (2^{-3} \times 7).
6468
7 times 2 times 3 is equal to 42.
2 * 2 * 5 * 7 * 11 = 1540
2 × 7 × 2 × 3 = 84
2 times 7 is 14 since 2 groups of 7 equals 14.
To calculate (2) cubed ((2^3)), you get (2 \times 2 \times 2 = 8). For (7) squared ((7^2)), you get (7 \times 7 = 49). Now, multiply these two results together: (8 \times 49 = 392). Therefore, (2) cubed times (7) squared equals (392).
The solution of 2 times 22 over 7 is 4. This calculation involves multiplying 2 by 22 to get 44, then dividing by 7 to get the final result of 4. The order of operations dictates that multiplication is performed before division in this equation.