7+5q = -3 5q = -3-7 5q =-10 q = -2
Look at it this way: If p = 1, then 7p = 7. What plus 7 equals -3? Adding 7 to -10 would equal -3, so all we have to figure out is what times 5 would equal -10. 5 times -2 would equal -10 so q equals -2.
8p+5 = 11+7p= 8p-7p = 11-5p = 6
14 + 6p = 6 + 7p 8 = p
7p + 2 = 5p + 8 7p - 5p = 8 - 2 2p = 6 p = 3
7+5q = -3 5q = -3-7 5q =-10 q = -2
Look at it this way: If p = 1, then 7p = 7. What plus 7 equals -3? Adding 7 to -10 would equal -3, so all we have to figure out is what times 5 would equal -10. 5 times -2 would equal -10 so q equals -2.
8p+5 = 11+7p= 8p-7p = 11-5p = 6
14 + 6p = 6 + 7p 8 = p
7p + 2 = 5p + 8 7p - 5p = 8 - 2 2p = 6 p = 3
4p+9-7p+2 -3p+11 p = 11/3
4p + 9 - 7p + 2 4p - 7p + 9 + 2 p(4 - 7) + 9 + 2 -3p + 11
11p+11
7p-2p equals = 5
Equilibrium occurs where Qd = QsQd - 128 + 9p = 0Qd = 128 - 9pQs + 32 - 7p = 0Qs = 7p - 327p - 32 = 128 - 9p16p = 160p = 10
15 + 3 = 7p - 4p ie 18 = 3p so p = 6
5p + 4y