7x + 8 = 84 Subtract 8 from bith sides: 7x = 76 Divide both sides by 7: x = 76/7 = 10.8571428...
19
7x2+49x+84 = 0 Divide all terms by 7: x2+7x+12 = 0 Factorize: (x+3)(x+4) = 0 Therefore the x intercepts are -3 and -4
x - 12 = 91 - 84x - 12 = 7x = 19
7=84 --=-- 10=x 7x=840 ---=---- 7 = 7 x = 120 x equals how many oz 10 cubes can hold
7x + 8 = 84 7x = 84 - 8 x = 76/7 x = 10.8571
84
3x + 4x = 847x = 84divide both sides by 7x = 12
7x + 8 = 84 Subtract 8 from bith sides: 7x = 76 Divide both sides by 7: x = 76/7 = 10.8571428...
It is an algebraic expression which is equivalent to 7x - 118.
19
7x - 18 = 66, solve for x. First step is to add 18 to both sides. So 7x = 84. Now divide by sides by 7 to get x = 12
P = 7x; 84 in.
7x2+49x+84 = 0 Divide all terms by 7: x2+7x+12 = 0 Factorize: (x+3)(x+4) = 0 Therefore the x intercepts are -3 and -4
x - 12 = 91 - 84x - 12 = 7x = 19
7x^3. That is 7x cubed.... or 7x*7x*7x (where * means multiply). You should get 343x
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