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To solve the expression (8 - 2 \times 3), you should follow the order of operations, which states that multiplication should be performed before subtraction. First, calculate (2 \times 3) to get (6). Then, subtract (6) from (8), resulting in (2). Therefore, (8 - 2 \times 3 = 2).
What else can I help you with?
What number comes next in the series 1-1-2-6-24?
I believe it is 120. * * * * * That is a belief which may or may not be justified. I suggest 76, with the following justification: Fit the polynomial t(n) = (9x4 - 82x3 + 279x2 -398x + 216)/24 for n = 1, 2, 3, etc.
What are the 82 times tables?
I didn't know how much you needed so I went up to 82x82. 82x1=82, 82x2=164, 82x3=246, 82x4=328, 82x5=410, 82x6=492, 82x7=574, 82x8=656, 82x9=738, 82x10=820, 82x11=902, 82x12=984, 82x13=1066, 82x14=1148, 82x15=1230, 82x16=1312, 82x17=1394, 82x18=1476, 82x19=1558, 82x20=1640, 82x21=1722, 82x22=1804, 82x23=1886, 82x24=1968, 82x25=2050, 82x26=2132, 82x27=2214, 82x28=2296, 82x29=2378, 82x30=2460, 82x31=2542, 82x32=2624, 82x33=2706, 82x34=2788, 82x35=2870, 82x36=2952, 82x37=3034, 82x38=3116, 82x39=3198, 82x40=3280, 82x41=3362, 82x42=3444, 82x43=3526, 82x44=3608, 82x45=3690, 82x46=3772, 82x47=3854, 82x48=3936, 82x49=4018, 82x50=4100, 82x51=4182, 82x52=4264, 82x53=4346, 82x54=4428, 82x55=4510, 82x56=4592, 82x57=4674, 82x58=4756, 82x59=4838, 82x60=4920, 82x61=5002, 82x62=5084, 82x63=5166, 82x64=5248, 82x65=5330, 82x66=5412, 82x67=5494, 82x68=5576, 82x69=5658, 82x70=5740, 82x71=5822, 82x72=5904, 82x73=5986, 82x74=6068, 82x75=6150, 82x76=6232, 82x77=6314, 82x78=6396, 82x79=6478, 82x80=6560, 82x81=6642, 82x82=6724
