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To find everything it's divisible by, you first need to find its prime factors. In this case, it's clearly divisible by 10, so the first two prime factors are 2 and 5. This leaves us with 89123, which is prime. To find all the numbers that 891230 divides by, we just need to combine these prime factors:
2x5 = 10
2x89123 = 178246
5x89123 = 445615
Thus 891230 is divisible by 1, 2, 5, 10, 89123, 178246, 445165 and 891230.
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What is a number that divisible by 2 and also divisible by 8?
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If a number is divisible by co prime numbers then it is also divisible by their?
It is divisible by their factors. It is also divisible by their product.
Is 238 divisible by 6?
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If a number is not divisible by 10 then itis not divisible by 5?
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A number is divisible by 6 if and only if it is divisible by 3?
If this is a T-F question, the answer is false. It is true that if a number is divisible by 6, it also divisible by 3. This is true because 6 is divisible by 3. However, the converse -- If a number is divisible by 3, it is divisible by 6, is false. A counterexample is 15. 15 is divisible by 3, but not by 6. It becomes clearer if you split the question into its two parts. A number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. A number is divisible by 6 only if it is divisible by 3? True.
