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How do you write 895 in expanded form?
The Expanded Notation of 895 = (8 x 102) + (9 x 101) + (5 x 100)
What is four fifths of 895?
4/5 of 895 is 716.
What is 40 percent of 895?
40 percent of 895 is 358.
What is 328 623 895 in roman numerals?
well that's an easy one 328 = CCCXXVIII 623 = DCXXIII 895 = DCCCXCV (fyi the dots are there for no reason) sorry i can't find one that would translate all 9 digits but: . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . _ _ _ three hundred and twenty eight million = |X|X|X| XXVIII M quite literally means: 300mil 28 thou then we have 623,000 = DCXXIII M and finally 895 which is very easy 895 = XCM (5 before 100 before 1000) . . . . . . . . . . . . . . . . . . . . . . _ _ _ so all together that makes |X|X|X| XXVIII MDC XXIII M hope i helped! (btw this is estimated my source is below) http://www.roman-Britain.org/numerals.htm it was easy but I'm used to doing sums like that
What is the answer to 31 x 49?
31 x 49 = 1519
What is 895 times 509?
895 x 509 = 455,555.
How do you write 895 in expanded form?
The Expanded Notation of 895 = (8 x 102) + (9 x 101) + (5 x 100)
What is 9 times 895 using subtraction and the distributive property?
9 x 895 = (9 x 900) - (9 x 5) = 8100 - 45 = 8055
What is 2.3 percent of 895?
2.3% of 895= 2.3% * 895= 0.023 * 895= 20.585
What are factors of 895?
They are: 1, 5, 179 and 895
How many grams is 895 milligrams?
895 mg = 0.895 g
What is 895 kilometers in miles?
895 kilometers = 556.1 miles
What is four fifths of 895?
4/5 of 895 is 716.
What is 40 percent of 895?
40 percent of 895 is 358.
What are some of the factors of 895?
1, 5, 179, 895
What are the factors of x to the power 6 plus nine?
x6 + 9= x6 - (-9) since i2 = -1= (x3)2 - 9i2 factor the difference of two squares= (x3 + 3i)(x3 - 3i) since 3 = (31/3)3 and -i = i3 we can write:= [x3 - (31/3)3i3] [x3 + (31/3)3i3]= [x3 - (31/3i)3] [x3 + (31/3i)3] factor the sum and the difference of two cubes= [(x - 31/3i)(x2 + 31/3ix + (31/3)2i2)] [(x + 31/3i)(x2 - 31/3ix + (31/3)2i2)]= [(x - 31/3i)(x2 + 31/3ix - (31/3)2)][(x + 31/3i)(x2 - 31/3ix - (31/3)2)]Thus, we have two factors (x - 31/3i) and (x + 31/3i),so let's find four othersAdd and subtract x2/4 to both trinomials[x2 - x2/4 + (x/2)2 + 31/3ix - (31/3)2] [x2 - x2/4 + (x/2)2 - 31/3ix - (32/3)2] combine and factor -1= {3x2/4 - [((x/2)i))2 - 31/3ix + (31/3)2]}{3x2/4 - [((x/2)i))2 + 31/3ix + (32/3)2]} write the difference of the two squares= {((3)1/2x/2))2 - [(x/2)i - 31/3]2}{((3)1/2x/2))2 - [(x/2)i + 32/3]2]} factor the difference of two squares= {[(31/2/2)x - ((1/2)i)x - 31/3)] [((31/2/2)x + ((1/2)i)x - 31/3)]} {[((31/2/2)x) - (((1/2)i)x + 31/3)] [((31/2/2)x) + ((1/2)i)x + 31/3)]}= {[(31/2/2)x - ((1/2)i)x + 31/3)] [((31/2/2)x + ((1/2)i)x - 31/3)]} {[((31/2/2)x) - ((1/2)i)x - 31/3)] [((31/2/2)x) + ((1/2)i)x + 31/3)]} simplify= {[((31/2 - i)/2))x + 31/3)] [((31/2 + i)/2))x - 31/3)]} {[((31/2 - i)/2))x - 31/3)] [((31/2+ i)/2))x + 31/3)]}so we have the 6 linear factors of x2 + 9.1) (x - 31/3i)2) (x + 31/3i)3) [((31/2 - i)/2))x + 31/3)]4) [((31/2 + i)/2))x - 31/3)]5) [((31/2 - i)/2))x - 31/3)]6) [((31/2+ i)/2))x + 31/3)]Check: Multiply:[(1)(2)][(3)(5)][(4)(6)]A) (x - 31/3i)(x + 31/3i) = x +(31/3)2B) [((31/2 - i)/2))x + 31/3)] [((31/2 - i)/2))x - 31/3)] = [(1 - (31/2)i)/2]x2 - (31/3)2C) [((31/2 + i)/2))x - 31/3)][((31/2+ i)/2))x + 31/3)] = [(1 + (31/2)i)/2]x2 - (31/3)2Multiply B) and C) and you'll get x4 - (31/3)2x2 + (31/3)4Now you have:[x +(31/3)2][x4 - (31/3)2x2 + (31/3)4] = x6 + 9
What equal to 31 in multiplication?
1 x 31, 2 x 31/2 , 3 x 31/3 etc. 31 is a prime number.
