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1/(radical 13 plus 10)
4+4=8+0=8+1=9+1=10+0=10+1=11 It equals 11. You're welcome.
x2+12x-13=0 The factor of x2+12x-13 is: (x+13)(x-1) So: x+13 = 0 or x-1 = 0 The answer is: x=-13 or x=1
8(1+5x) +5 = 13+5x => 8+40x + 5 = 13 +5x => 13+40x = 13+5x => 13-13+40x = 13-13+5x => 40x = 5x => 40x - 5x = 0 => 35x = 0 => 35x/35 = 0/35 => x = 0
(13)10 = (1 1 0 1)2
Plus 12 plus -13 plus plus 1 can be rewritten in mathematical terms as: 12+(-13)+1 or 12-13+1 12-13+1 =-1+1 =0
1/(radical 13 plus 10)
4+4=8+0=8+1=9+1=10+0=10+1=11 It equals 11. You're welcome.
[(4 * 10^2) + (0 * 10^1) + (0 * 10^0)] + [(1 * 10^1) + (0 * 10^0)]
13/10 or 1 & 3/10 or 1.3It is 1/2 plus 4/5 = 13/10 or 1.3 as a decimal
x2+12x-13=0 The factor of x2+12x-13 is: (x+13)(x-1) So: x+13 = 0 or x-1 = 0 The answer is: x=-13 or x=1
8(1+5x) +5 = 13+5x => 8+40x + 5 = 13 +5x => 13+40x = 13+5x => 13-13+40x = 13-13+5x => 40x = 5x => 40x - 5x = 0 => 35x = 0 => 35x/35 = 0/35 => x = 0
1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 - 1 + 1 + 1 + 1 + 1 + 1 x 0= (1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1) + (1 - 1) + (1 + 1 + 1 + 1) + (1 x 0)= 9 + 0 + 4 + 0= 13It depends on if the entire equation is being multiplied by 0 or just the last plus 1. If it is just the last plus 1 then the answer is 13 like shown above. If the entire problem is being multiplied by 0 then the answer is 0.
(13)10 = (1 1 0 1)2
13 and three fourths
10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 + 0 = 55
10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 + 0 = 55