what is the perimeter of a rectangle 8mm by 3m
A rectangular prism with a length of 11m, width of 8m and height of 3m has a volume of 264m3
firstly, 1 metre is 2 sets of 50cm 2m=4 sets of 50cm 3m=6 sets of 50cm 4m=8 sets of 50cm 5m=10 sets of 50cm 6m=12 sets of 50cm 7m=14 sets of 50cm 8m=16 sets of 50cm 9m=18 sets of 50cm 10m=20 sets of 50cm 11m=22 sets of 50cm 12m=24 sets of 50cm 13m=26 sets of 50cm 14m=28 sets of 50cm 15m=30 sets of 50cm 16m=32 sets of 50cm 17m=34 sets of 50cm 18m=36 sets of 50cm 19m=38 sets of 50cm 20m=40 sets of 50cm 21m=42 sets of 50cm 22m=44 sets of 50cm 23m=46 sets of 50cm 24m=48 sets of 50cm 25m=50 sets of 50cm 26m=52 sets of 50cm 27m=54 sets of 50cm 28m=56 sets of 50cm 29m=58 sets of 50cm 30m=60 sets of 50cm if the measurements are 8 by 30 metres, this means that the area is covered by 16 times 60 amount of tiles which is the amount of 960 tiles altogether Source: A successful Graduate of Cambridge University
150.796 m2 (rounded)
(L + W) x 2 (8 + 3) x 2 = 11 x 2 = 22m
The answer is 22.02 meters
Isn't it the sum of all sides? 8m+8m+3m+3m = 22m
350cm/50cm=7
If you mean an area measuring 3m x 8m, the answer is 22m !
what is the perimeter of a rectangle 8mm by 3m
To neutralize the 25ml of 3M acid, you would need to find the number of moles of acid present, which is 25ml * 3M = 75 millimoles. Then, you would need the same number of millimoles of the 8M base to neutralize it, so you would need 75 millimoles / 8M = 9.38ml of the 8M base.
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96m3
If you put an ant down on the rectangle and start him walking along the line, the 'perimeter' is the distance he has to walk in order to get back to where he started, if he stays on the line. If you put him down on a corner of this one, he has to walk (8m + 3m + 8m + 3m) = 22m. That's the perimeter.
A rectangular prism with a length of 11m, width of 8m and height of 3m has a volume of 264m3
-3m = 5m+8 -3m-5m = 8 -8m = 8 m = -1
11m + 4n - 3m +11n = 8m + 15n