8(x^2)(yz)(16x)(y^2)(z^2)-24xy(z^2). Combine like terms: 128(x^3)(y^3)(z^3)-24xy(z^2). Now, find the common factors and move them to the left. They both share 8xy(z^2), so, we can combine make the expression look like this: 8xy(z^2)[16z(x^2)(y^2)-3]. This is factored completely.
9x squared plus 16 = 0 factored is plus and minus 4/3 i.
16 - y2 = (4 - y)*(4 + y)
It can't be factored because its discriminant is less than zero.
To factor the expression (4 + 16x + 28y), we first observe that the coefficients 4, 16, and 28 have a common factor of 4. Factoring out 4 gives us: [ 4(1 + 4x + 7y) ] Thus, the completely factored form of the expression is (4(1 + 4x + 7y)).
16 squared is 256.
9x squared plus 16 = 0 factored is plus and minus 4/3 i.
77r + 74r - 16 = 151r - 16 and that cannot be factored further.
9x squared plus 16 = 0 factored is plus and minus 4/3 i.
16 - y2 = (4 - y)*(4 + y)
3x² - 22x - 16 = (3x + 2)(x - 8)
I guess that should be 3 times (x squared) minus 48: 3x2 - 48 = 3(x2 - 16) = 3(x + 4)(x - 4)
It can't be factored because its discriminant is less than zero.
(9a+4)(81a2-36a+16)
No.
9 squared is 81 and 16 squared is 256
16 to the 4th power, or 16 x 16 x 16 x 16 = 65,536
To factor the expression (4 + 16x + 28y), we first observe that the coefficients 4, 16, and 28 have a common factor of 4. Factoring out 4 gives us: [ 4(1 + 4x + 7y) ] Thus, the completely factored form of the expression is (4(1 + 4x + 7y)).