There are 9 choices for the first digit, 8 for the second, 7 for the third, and 6 for the last. So there are 9x8x7x6=3024 "permutations" That means the order does matter. If the order does not matter, divide that number by 4!=4x3x2x1 9C4 is 126
93
it is equal to equal lol:P
Yes. If equals are added to equals, then the results of the additions are equal.
it equals 4c
The probability of 4 aces being in a hand of 9 cards is: 9C4 ∙ (4/52)∙(3/51)∙(2/50)∙(1/49)∙(48/48)∙(47/47)∙∙∙(44/44) = 0.0004654... ≈ 0.0465% where 9C4 = 9!/[(9-3)!∙3!] = 126
There are: 9C4 = 126
126. In mathematical notation it could be written as 9C4 or 9C5. It is known as the binomial coefficient.
The answer is 9C4 = 9*8*7*6/(4*3*2*1) = 126 ways.
(8C3 x 9C4)/17C7= (56 x 126)/19448= about 36.3%
one equals
That 8 might equal D. Trashed. "Eight Equals D" is: 8=D Which is a penis smiley -.- ~ Skullcandy88
There are 9 choices for the first digit, 8 for the second, 7 for the third, and 6 for the last. So there are 9x8x7x6=3024 "permutations" That means the order does matter. If the order does not matter, divide that number by 4!=4x3x2x1 9C4 is 126
equals D repeater
(It's a penis) 8=====D 8 = balls D = head
93
93