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How do you write the sum of x and 6 is the product of 9 and 2?
x + 6 = 9 * 2
What is 6 times 2 times 9?
6 x 2 x 9 = 108
What is the product of 6 x 6 x 7 x 7 x 9 x 9 in exponential form?
6^2 * 7^2 * 9^2 36 * 49 * 81 = 142,884
What is 6 times 9 divided by 2?
6 x 9 / 2 = 27
How can you make 2 6 9 9 equal 24?
9 x ( 6/9 + 2 ) = 24
X2 - 9x - 6 equals 0?
x2 - 9x - 6 = 0 x2 - 9x + (9/2)2 = 6 + (9/2)2 (x - 9/2)2 = 6 + 81/4 x - 9/2 = ± √105 / 2 x = (9 ± √105) / 2
What is nine plus four cubed times twenty minus eight in parentheses divided by two plus six?
I can't tell from your question where the parentheses start and end, so I'm just guessing: 9 + 4³ x (20 - 8) ÷ 2 + 6 = 9 + 4³ x (12) ÷ 2 + 6 = 9 + 4³ x 12 ÷ 2 + 6 = 9 + (4x4x4) x 12 ÷ 2 + 6 = 9 + 64 x 12 ÷ 2 + 6 = 9 + (64 x 12 ÷ 2) + 6 = 9 + (768 ÷ 2) + 6 = 9 + (384) + 6 = 9 + 384 + 6 = 393 + 6 = 399
What is the prime factorization of 9 8 14 and 6?
3 x 3 = 9 2 x 2 x 2 = 8 2 x 7 = 14 2 x 3 = 6
What numbers can you mmuliply to get 18?
1 x 18, 2 x 9, 3 x 6, 6 x 3, 9 x 2, 18 x 1
What is x 6-2x 7-3x -9?
6 - (2 x 7) - (3 x (-9)) = 19
What three dights can you multiply to get 108?
9, 2 and 6. 9 x 2 = 18 18 x 6 = 108
What equals in 36 multiplication?
1 x 36, 2 x 18, 3 x 12, 4 x 9, 6 x 6.
How so solve x over 6 equals 18 over 9?
18 over 9 = 2 so x over 6 = 2 making x = 6 x 2 ie 12
What are the factors of 54?
The factors of 54 are 1, 2, 3, 6, 9, 18, 27, and 54. The factor pairs of 54 are 1 x 54, 2 x 27, 3 x 18, and 6 x 9The factors of 54 are: 1 2 3 6 9 18 27 54.1, 2, 3, 6, 9, 18, 27, 54The factors of 54 are: 1, 2, 3, 6, 9, 18, 27, & 541, 2, 3, 6, 54, 27, 18, 9
What you 9 x 6 - 7 x 2- 7?
9*6-7*2-7 54-14-7 33
X minus 2 divided by 3x plus 9 times 2x plus 6 divided by 2x minus 4?
I assume you wish to simplify the expression (x - 2)/(3x + 9) . (2x + 6)/(2x - 4) = (x - 2)(2x + 6) / [(3x + 9)(2x - 4)] = 2(x - 2)(x + 3) / [6(x + 3)(x - 2)] = 1/3.
The product of your number and 3 is the same product as twice 9 What is your number?
3x = 2 x 9 2 x 9 = 18 3x = 18 18/x = 6 Therefore, x = 6
