Given the two equaitons Ax + By = C Dx + Ey = F The values for x and y that satisfy both equations is x = CE -BF y = CD-AF AE -BD , -AE+BD A full explanation can be found here http://math-journal.blogspot.com/p/algebra.html
Let's draw the parallelogram ABCD in which both pairs of opposite sides are parallel and congruent.From the vertices A and C draw the altitudes AE and CF respectively to the sides DC and AB of the parallelogram, which separates it into two congruent right triangles AED and CFB, and the rectangular AFCE. So that the area of the parallelogram equals to2(AAED) + AAFCE= 2[(DE x AE)/2] + (EC x AE)= (DE x AE) + (EC x AE)= (DE + EC)AE= DC x AE= base x heightThus, the area of any parallelogram equals to the product of its base and height.
ind the area of the rhombus if AE = 20 m and DE = 32 m.
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