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Anonymous
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It is: b+b+b = 3b
[a+b]2 = [a+b]*[a+b]= a*a + a*b + b*a + b*b= a2 + 2ab + b2
(B^-1)B = 1 B^(-1xB) = 1/(B^B)
B4 or B*B*B*B