30 c
So we have: the mean; (a + b + c)/3 = 10 yield that a + b + c = 30 (numbers in order) the range; c - a = 2 yield that c = a + 2 the median; b = 10.3 Substituting this information, we have: a + 10.3 + a + 2 = 30 2a = 17.7 a = 17.7/2 a = 8.85 yield that c = 10.85 So the numbers are 8,85, 10.3, and 10.85. Or, since b = 10.3 yield that a + c = 19.7 a + c = 19.7 -a + c = 2 add both equations 2c = 21.7 c = 18.85 which yield a = 8.85
0
21 / 30 is a 70%, or a C-.
30 - 32 = -2 -2 divided by 9 is -0.2222222 -0.2222222 times 5 = -1.1111111 So 30⁰F = -1.1111111⁰C
30 c
c - 30 = 27-------------c = 57
c in this case stand for "circa" latin for "around" or "in the general time of". Used by historians to denote an aproximate time for which an exact date is inappropriate. Means "somewhere around 69-30 BC"
30 c
30 F = (30 - 32) x 5/9 C = -10/9 C = - 1.1111 C
30 c = 86 f 30 f = -1.11 c
30 is the caliber or bore size. W is winchester. C is center. F is fire
mean or average = (a + b + c) / 3 = 10 so a + b + c = 10 * 3, so a + b + c = 30, so take your pick, 2 + 10 + 18, 11 + 4 + 15 etc
30 c
So we have: the mean; (a + b + c)/3 = 10 yield that a + b + c = 30 (numbers in order) the range; c - a = 2 yield that c = a + 2 the median; b = 10.3 Substituting this information, we have: a + 10.3 + a + 2 = 30 2a = 17.7 a = 17.7/2 a = 8.85 yield that c = 10.85 So the numbers are 8,85, 10.3, and 10.85. Or, since b = 10.3 yield that a + c = 19.7 a + c = 19.7 -a + c = 2 add both equations 2c = 21.7 c = 18.85 which yield a = 8.85
300 mils
Tropical forests can be around 20o to 25o C Temperate forests can be around -30° C to 30° C