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How do you solve 2r-1 equals 9?
2r-1=9 2r =10 r =5
R plus s equals 4 2r plus 3s equals 8?
r + s = 4 and 2r + 3s = 8 multiply the first equation by 2 giving 2r + 2s = 8 subtract this from the second equation giving s = 0 So r = 4 and s = 0.
16r2 plus 18r plus 5 equals 0?
Solving for r: 16r2+18r+5=0 (2r+1)(8r+5)=0 2r+1=0 and 8r+5=0 2r=-1 .......... 8r=-5 r= -1/2 ........ r= -5/8
What formula equates to pie?
any formula with pi in it can be switched around so that pi is on one side of the equation and everything else is on the other side. ex. C = circumference of a circle r = radius of a circle C = 2 * pi * r or C / 2 = pi * r or C / (2r) = pi Therefore: pi = C / (2r)
What is the answer of R equals 11m C equals?
The answer depends on what R and C are.
What is the answer to -7 equals 7-2r?
If: -7 = 7-2r Then: r = 7
What is 7-2r equals 13?
If: 7 -2r = 13 Then: r = -3
How do you solve 2r-1 equals 9?
2r-1=9 2r =10 r =5
How do you solve 10 plus r equals 2r?
10+r = 2r Subtract r from both sides:- r = 10
How do you do absolute 2r plus 9 absolute equals 5?
|2r + 9| = 5 So 2r + 9 = 5 or 2r + 9 = -5 so that 2r = -4 or 2r = -14 r = -2 or r = -7
What is the answer to the problem 2r-5 equals 11?
r=8
What is r2 equals -2r plus 35?
r -31
What fraction of a circumference equals the radius?
2r(pi)=C where C is circumference. Therefore the radius equals C/2(pi)
R plus s equals 4 2r plus 3s equals 8?
r + s = 4 and 2r + 3s = 8 multiply the first equation by 2 giving 2r + 2s = 8 subtract this from the second equation giving s = 0 So r = 4 and s = 0.
How do you find the radius of a circle if the circumference is 68?
C (Circumference) = 3.14 (pi)*D (diameter) r (radius) = 0.5D and D = 2r So circumference can also be C=3.14*2r Then, solve 68 = 3.14*2r to get r = 10.83
If r is the radius of a circle and d is its diameter what is an equivalent formula for the circumference C 2r?
c=πd
16r2 plus 18r plus 5 equals 0?
Solving for r: 16r2+18r+5=0 (2r+1)(8r+5)=0 2r+1=0 and 8r+5=0 2r=-1 .......... 8r=-5 r= -1/2 ........ r= -5/8
