2r-1=9 2r =10 r =5
r + s = 4 and 2r + 3s = 8 multiply the first equation by 2 giving 2r + 2s = 8 subtract this from the second equation giving s = 0 So r = 4 and s = 0.
Solving for r: 16r2+18r+5=0 (2r+1)(8r+5)=0 2r+1=0 and 8r+5=0 2r=-1 .......... 8r=-5 r= -1/2 ........ r= -5/8
The answer depends on what R and C are.
any formula with pi in it can be switched around so that pi is on one side of the equation and everything else is on the other side. ex. C = circumference of a circle r = radius of a circle C = 2 * pi * r or C / 2 = pi * r or C / (2r) = pi Therefore: pi = C / (2r)
If: 7 -2r = 13 Then: r = -3
If: -7 = 7-2r Then: r = 7
2r-1=9 2r =10 r =5
10+r = 2r Subtract r from both sides:- r = 10
|2r + 9| = 5 So 2r + 9 = 5 or 2r + 9 = -5 so that 2r = -4 or 2r = -14 r = -2 or r = -7
r -31
r=8
2r(pi)=C where C is circumference. Therefore the radius equals C/2(pi)
r + s = 4 and 2r + 3s = 8 multiply the first equation by 2 giving 2r + 2s = 8 subtract this from the second equation giving s = 0 So r = 4 and s = 0.
C (Circumference) = 3.14 (pi)*D (diameter) r (radius) = 0.5D and D = 2r So circumference can also be C=3.14*2r Then, solve 68 = 3.14*2r to get r = 10.83
c=πd
Solving for r: 16r2+18r+5=0 (2r+1)(8r+5)=0 2r+1=0 and 8r+5=0 2r=-1 .......... 8r=-5 r= -1/2 ........ r= -5/8