If: C = 2r
Then: r = C/2
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2r-1=9 2r =10 r =5
r + s = 4 and 2r + 3s = 8 multiply the first equation by 2 giving 2r + 2s = 8 subtract this from the second equation giving s = 0 So r = 4 and s = 0.
The answer depends on what R and C are.
Solving for r: 16r2+18r+5=0 (2r+1)(8r+5)=0 2r+1=0 and 8r+5=0 2r=-1 .......... 8r=-5 r= -1/2 ........ r= -5/8
any formula with pi in it can be switched around so that pi is on one side of the equation and everything else is on the other side. ex. C = circumference of a circle r = radius of a circle C = 2 * pi * r or C / 2 = pi * r or C / (2r) = pi Therefore: pi = C / (2r)