F = 9/5 C + 32 = (9/5) x 10 + 32 = 18 + 32 = 50
2f + 8 = 103 2f = 95 f = 47.5
Mathematically speaking: f = 1.8c + 32 in terms of functions is: f(c) = 1.8c + 32 so: f(-15) = 1.8 * -15 + 32 = -27 + 32 f(-15) = +5 So, -15 Celsius is 5 Fahrenheit. Simples.
(25 x 1.8) + 32 = 45 + 32 = 77F
Because the freezing temperature of water is defined as zero Celsius and 32 Fahrenheit.
F = 9/5 C + 32 = (9/5) x 10 + 32 = 18 + 32 = 50
2f + 8 = 103 2f = 95 f = 47.5
Mathematically speaking: f = 1.8c + 32 in terms of functions is: f(c) = 1.8c + 32 so: f(-15) = 1.8 * -15 + 32 = -27 + 32 f(-15) = +5 So, -15 Celsius is 5 Fahrenheit. Simples.
(25 x 1.8) + 32 = 45 + 32 = 77F
This does mean (not does means): -24 F (Fahrenheit) is 8 F below the freezing point of water, 32 F.
To convert Fahrenheit to Celsius, subtract 32 from the Fahrenheit value and then multiply by 5/9. So for 95°F, the calculation would be (95-32) * 5/9 = 35°C.
95°C = 203°F: 95°C multiplied by 9/5 +32 = 203°F
Because the freezing point of water is zero-C but 32-F. The C-temp tells you (how many C-degrees above freezing it is), because C starts at zero. But the F-temp has to be 32 more than (how many F-degrees above freezing it is), because F starts at 32, not at zero.
95°F = 35°C(95°F - 32) multiplied by 5/9 = 35°C
Because the freezing temperature of water is defined as zero Celsius and 32 Fahrenheit.
203°F The degree intervals on the Celsius scale number 100 between the freezing and boiling points of water (0° and 100°), whereas there are 180 intervals between them in the Fahrenheit scale (32° and 212°). So the conversion between scales is 1° C = 1.8°F (9/5°). The conversion of temperatures involves adding or removing the 32° between starting points and changing the scale of degrees. T (in °F) = (T-32)x(5/9) °C and T(in °C)= (9/5)xT plus 32° 95°C = 95x(9/5) plus 32 = 171+32 = 203°F
wth??