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Evaluating the indicated expressions if g-7-h-35?
= g-7-h-35=g-h-42 =
What is index in group theory?
Say we have a group G, and some subgroup H. The number of cosets of H in G is called the index of H in G. This is written [G:H].If G and H are finite, [G:H] is just |G|/|H|.What if they are infinite? Here is an example. Let G be the integers under addition. Let H be the even integers under addition, a subgroup. The cosets of H in G are H and H+1. H+1 is the set of all even integers + 1, so the set of all odd integers. Here we have partitioned the integers into two cosets, even and odd integers. So [G:H] is 2.
What is subgroup in mathematics?
In mathematics, a subgroup H of a group G is a subset of G which is also a group with respect to the same group operation * defined on G. H contains the identity element of G, is closed with respect to *, and all elements of H have their inverses in H as well.
How do you prove Cayley's theorem which states that every group is isomorphic to a permutation group?
Cayley's theorem:Let (G,$) be a group. For each g Є G, let Jg be a permutation of G such thatJg(x) = g$xJ, then, is a function from g to Jg, J: g --> Jg and is an isomorphism from (G,$) onto a permutation group on G.Proof:We already know, from another established theorem that I'm not going to prove here, that an element invertible for an associative composition is cancellable for that composition, therefore Jg is a permutation of G. Given another permutation, Jh = Jg, then h = h$x = Jh(x) = Jg(x) = g$x = g, meaning J is injective. Now for the fun part!For every x Є G, a composition of two permutations is as follows:(Jg ○ Jh)(x) = Jg(Jh(x)) = Jg(h$x) = g$(h$x) = (g$h)$x = Jg$h(x)Therefore Jg ○ Jh = Jg$h(x) for all g, h Є GThat means that the set Ђ = {Jg: g Є G} is a stable subset of the permutation subset of G, written as ЖG, and J is an isomorphism from G onto Ђ. Consequently, Ђ is a group and therefore is a permutation group on G.Q.E.D.
What is the algebraic expression for 10 times the sum of g over h?
There seems to be something missing in the question. But, as it stands, the expression is 10*g/h
