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What is the standard IRQ setting for a math coprocessor?
What is the standard IRQ setting for a math coprocessor?
What is 1 plus 8 plus 5 plus 4 plus 5 plus 5-5-5-5-5-5-5-5-5-5?
1+8+5+4+5+5-5-5-5-5-5-5-5-5-5 = -17
How many different ways can you change a dollar using only half dollars nickels and quarters?
50 50 25 25 25 25 20 x .05 50 25 25 50 25 5 5 5 5 5 50 5 5 5 5 5 5 5 5 5 5 25 25 25 5 5 5 5 5 25 25 5 5 5 5 5 5 5 5 5 5 25 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5
How do you get numbers by only using four fives?
0: (5x5)-(5x5) 1: (5:5)+5-5 2: (5:5)+(5:5) 3: (5+5+5):5 4: [(5x5)-5]:5 5: [(5-5)x5]+5 6: [(5x5)+5]:5 7: [(5+5):5]+5 10: 5+5+5-5 11: (5:5)+5+5 15: (5x5)-5-5 20: 5+5+5+5 24: (5x5)-(5:5) 25: (5x5)+5-5 26: (5x5)+(5:5) 30: [(5:5)+5]x5 35: (5x5)+5+5 45: [(5+5)x5]-5 50: (5x5)+(5x5) 55: [(5+5)x5]+5 75: (5+5+5)x5 120: (5x5x5)-5 130: (5x5x5)+5 625: 5x5x5x5
How do you get 37 using five 5's?
Here is one answer:((5+5)/5 )^5 +5Details:((5+5)/5 )^5 +5= ((10)/5 )^5 +5= 2^5 +5= 32 + 5= 37Another answer:(5*5)+(5!/(5+5))Details:(5*5)+(5!/(5+5))=25 + (5!/10)=25 + (120/10)=25 + 12=37
