In the context of coordinates, "N" typically represents the north direction in geographic coordinates. Therefore, "11 23 35 N 59" refers to a specific latitude of 11 degrees, 23 minutes, and 35 seconds north of the equator, with "59" likely indicating the longitude. The exact longitude would need clarification, as it typically comes in a format such as degrees, minutes, and seconds or a decimal.
t(n) = 6*n - 1 where n = 1, 2, 3, ...
11, 14, 19, 26 and 35.
The number of combinations for selecting 6 numbers from a set of 59 can be calculated using the formula for combinations, which is ( C(n, k) = \frac{n!}{k!(n-k)!} ). For this case, ( n = 59 ) and ( k = 6 ), resulting in ( C(59, 6) = \frac{59!}{6!(59-6)!} = 45,379,620 ). Therefore, there are 45,379,620 different combinations of 6 numbers that can be chosen from the numbers 1 to 59.
Let the numbers by 'm' & 'n' Hence m + n = 12 mn = 35 Hence m = 35/n Substitute 35/n + n = 12 Multiply through by 'n' 35 + n^2 = 12n n^2 - 12n + 35 = 0 It is now in Quadratic Form ; Factor ( n - 7)(n - 5) = 0 Hence n= 7 or n= 5 It follows that m = 5 , or m = 7
The simplest and most obvious sequence is given by the formula: X[n]=136 - n*7 This gives X[11]=59.
n + 6 * * * * * I suggest you try t(n) = 6n + 5 instead.
Let the smaller be n, then the larger is n+1; and: n + 4(n+1) = 59 → n + 4n + 4 = 59 → 5n = 55 → n = 11 → the two consecutive integers are 11 and 12.
23-8 = 15 so 50-N = 15 N = 35
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
35°37′59″n 88°49′15″w
35° 9′ 47″ N, 33° 18′ 59″ E35.163056, 33.316389
49° 59′ 37″ N, 15° 43′ 23″ E49.993611, 15.723056
31°42′11″N 35°11′44″E
53°45′N 071°59′W
35° 41′ 46″ N, 51° 25′ 23″ E
Approximate latitude: 17°35′N to 18°35′N Approximate longitude: 76°'W to 78°30′W The coordinates of its capital, Kingston: Latitude: 17°59′N Longitude: 76°48′W
a (sub n) = 35 - (n - 1) x d