In the context of a 40-foot DV (Door Opening) container, "O" typically refers to the external dimensions, while "F" refers to the internal dimensions. The external dimensions of a 40-foot DV container are approximately 40 feet long, 8 feet wide, and 8.5 feet high. Internally, the dimensions are roughly 39.5 feet long, 7.7 feet wide, and 7.9 feet high, allowing for cargo space that can vary depending on the specific design and manufacturer of the container.
-40 f=-40 c
Unless graded on a curve, 40% is a F.
0 C = 32 F 100 C = 212 F 180 degrees F equals the measurement of 100 degrees C 9 degrees F therefore equals 5 degrees C -40 F is 72 degrees F below freezing -40 C is 40 degrees C below freezing Convert F to C 5 times -72 is -360 divided by 9 is -40 C convert C to F 9 times -40 is -360 divided by 5 is -40 F
To find ( f(x) ) when ( x = -5 ), substitute (-5) into the function ( f(x) = 5x + 40 ). This gives: [ f(-5) = 5(-5) + 40 = -25 + 40 = 15. ] Thus, ( f(-5) = 15 ).
-40 c = -40 f
NO , depending on the year and bodystyle you might be able to get ( 2 ) Ford F-150 trucks in a 40 FOOT long container
-40°F = -40°C
Either in a container covered with a lid or plastic wrap, or in a sandwich bag.
viscous force F=uA(dv/dr) u=(constant) Dynamic viscosity A=area dv/dr=Velocity gradient
-40 f=-40 c
At an altitude of 88,000 feet, temperatures can drop significantly, typically ranging from -40°F to -70°F (-40°C to -57°C). The exact temperature can vary depending on atmospheric conditions and geographic location. At such high altitudes, the air is very thin, contributing to the extreme cold.
We know, F = m*f, [ m = mass, f = accelaration] or,F = m*(dv/dt), [dv/dt = change of velocity with respect to time] or,F=m*(d^2x/dt^2) [v = dx/dt]. Solving this differential equation yields x=x0+v0*t+1/2*(F/m)*t^2 where x0, and v0 are the initial position and velocity, respectively.
viscous force F=uA(dv/dr) u=(constant) Dynamic viscosity A=area dv/dr=Velocity gradient
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Force (F) F = m.a and since a = dv/dt thus F = m.dv/dt Momentum (p) p = m.v and since a = dv/dt thus p = m.a.dt By switch dt from R.H.S. to L.H.S we get dp/dt = m.a thus F = dp/dt
-40°C is equal to -40°F.
Unless graded on a curve, 40% is a F.