0
The midpoint of the hypotenuse equidistant from all the vertices
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
What is the midpoint of (-8-7) and -(-7-8)?
The midpoint of the hypotenuse equidistant from all the vertices
What is the midpoint of (-8-7) and (-7-8)?
The midpoint of the hypotenuse equidistant from all the vertices
How do you show that from the right angle vertex to the midpoint of the hypotenuse is half the length of the hypotenouse?
All right triangles inscribed in a circle have their vertices on the circle and the hypotenuse as the circle's diameter. Thus the midpoint of the hypotenuse is the center of the circle nd all points on the circle are eqully as far from the center even so the vertex of the right angle.
What is the name of the point at which all of the triangle's perpendicular bisectors intersect?
Circumcenter, this is the center-point of a circle circumscribed around the triangle. If the triangle is obtuse, then this point is outside the triangle and if the triangle is a right triangle, then the point is the midpoint of the hypotenuse.
What does the midpoint formula give you the midpoint of?
it gives you the midpoint of the line segment you use the formula for
Which point of concurrency is always on the midpoint of the hypotenuse in a triangle?
The circumcenter is always on the midpoint of the hypotenuse when it is in a right triangle.
What is the midpoint of (-34) and (-6-1)?
The midpoint of the hypotenuse equidistant from all the vertices
What is the midpoint of (-8-7) and (-7-8)?
The midpoint of the hypotenuse equidistant from all the vertices
What is the midpoint of (-8-7) and -(-7-8)?
The midpoint of the hypotenuse equidistant from all the vertices
Prove that the the line segment joining the midpoint of the hypotenuse of a right triangle to the vertex of the right angle is equal to half the hypotenuse?
Simply by measuring it. Or by drawing a circle with a radius of half the hypotenuse and having the vertex of the right angle as its centre and if the midpoint of the hypotenuse just touches the circle then this proves it.
Where can the perpendicular bisectors of the side of a right triangle intersect?
Only at the midpoint of the hypotenuse.
Midpoint of hypotenuse of right triangle?
a^2 + b^2 = c^2 a and b are the distances for the side of the triangle and c is the hypotenuse(long side)
How do you show that from the right angle vertex to the midpoint of the hypotenuse is half the length of the hypotenouse?
All right triangles inscribed in a circle have their vertices on the circle and the hypotenuse as the circle's diameter. Thus the midpoint of the hypotenuse is the center of the circle nd all points on the circle are eqully as far from the center even so the vertex of the right angle.
Does a right-angled triangle have any symmetery?
If it is a 45-45-90 triangle, it will have symmetry from the 90 degree angle to the midpoint of the hypotenuse.
A chord of a circle is 9 inches long and its midpoint is 6inches from the center of the circle What is the radius of the circle?
Half of the chord, the distance of the midpoint from the center, and a radius, form a right triangle, with the radius as its hypotenuse. (4.5)2 + (6)2 = (radius)2 (20.25) + (36) = 56.25 = R2 Radius = 7.5 inches
What is midpoint postulate?
midpoint postulate
What is the name of the point at which all of the triangle's perpendicular bisectors intersect?
Circumcenter, this is the center-point of a circle circumscribed around the triangle. If the triangle is obtuse, then this point is outside the triangle and if the triangle is a right triangle, then the point is the midpoint of the hypotenuse.
