The given series consists of numbers that can be expressed as powers of 3: (9 = 3^2), (6561 = 3^8), and (43046721 = 3^{16}). The exponents are increasing in a pattern of doubling: (2, 8, 16). Thus, the next exponent should be (32), which means the missing number is (3^{32} = 1853020188851841).
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9, 81, 6561, 43046721, ...This would be the sequence 9^(2^(n-1))
square of 6561 is 43046721 square root is 81
There should only be four numbers in the question: 3, 9, 81 and 6561. Then the fifth is 43046721.
812= 6561812= 6561812= 6561812= 6561
65613 = 6561 x 6561 x 6561 = 282429536481