The given series consists of numbers that can be expressed as powers of 3: (9 = 3^2), (6561 = 3^8), and (43046721 = 3^{16}). The exponents are increasing in a pattern of doubling: (2, 8, 16). Thus, the next exponent should be (32), which means the missing number is (3^{32} = 1853020188851841).
9, 81, 6561, 43046721, ...This would be the sequence 9^(2^(n-1))
The series appears to be based on powers of 3. The first number, 9, is (3^2), the second number, 6561, is (3^8), and the third number, 43046721, is (3^{14}). The missing number should follow the pattern of increasing the exponent by 6, which gives us (3^4 = 81). Thus, the missing number in the series is 81.
square of 6561 is 43046721 square root is 81
The sequence given is 7, 6561, 43046721. These numbers can be expressed as powers of 7: (7^1), (7^4), and (7^6). The next term would logically follow the pattern of increasing powers of 7, specifically (7^8), which equals 5764801. Thus, the next number in the series is 5764801.
There should only be four numbers in the question: 3, 9, 81 and 6561. Then the fifth is 43046721.
9, 81, 6561, 43046721, ...This would be the sequence 9^(2^(n-1))
square of 6561 is 43046721 square root is 81
The numbers are being squared: 32 = 9 92 = 81 812 = 6561 65612 = 43046721
There should only be four numbers in the question: 3, 9, 81 and 6561. Then the fifth is 43046721.
Any multiple of that number: 6561 x 0 6561 x 1 6561 x 2 etc.
The factors of 387420489 are 1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683, 59049, 177147, 531441, 1594323, 4782969, 14348907, 43046721, 129140163, 387420489
812= 6561812= 6561812= 6561812= 6561
65613 = 6561 x 6561 x 6561 = 282429536481
6561 = 6561.0 or 6561 = 6561/1
12
6561^3 = 282,429,536,481.
The square root of 6561 is 81