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How do you make 2.65 out of dimes and nickels only using thirty-one coins?
This is a simple algebra question:d + n = 31.1d + .05n = 2.65Subsituting in for "d" using "n" we have:d = 31 - n3.1 - .1n + .05n = 2.65-0.05n = -0.45Solve for n:n = 9d + 9 = 31d = 22Thus, there are 9 nickels and 22 dimes.
How do you solve 25q plus 05n equals 10.50?
The "solution" is a pair of numbers that make the statement true when youplug in the numbers in place of 'q' and 'n'.So far, there are an infinite number of them. In fact, if you graph this equation, thegraph is a straight line, and every point on the line is a solution to the equation.If you expect to get one single number for 'q' and one single number for 'n', thatcan't happen until you have another equation to go along with this one. You alwaysneed the same number of equations as the number of 'unknowns' in them.(Here you have two 'unknowns' ... 'q' and 'n' .)
How do you know if a solution is a good solution?
what is the solution for a good nutrition
What are three examples of solutions?
There is the solution to a puzzle. There is a chemical solution There is an alloy There is a solution to an equation There is a solution to a problem
What is the answer to an equation called?
Solution
