An object 2.5 cm long is placed on the axis of a concave mirror on 30 cm radius of curvature at a distance of 10 cm away from it Find the position size and nature of the image formed?
The mirror equation for concave mirrors is 1/f = 1/do + 1/di, where f is the focal length, do is the object distance, and di is the image distance. Since the object distance is 10 cm from the mirror and the radius of curvature is 30 cm, the focal length (f) is half the radius of curvature, which is 15 cm. Substituting the values, you can find the image distance (di) which is -20 cm (negative indicates a real image). The magnification can be calculated using M = -di/do, which in this case is -20/-10 = 2. This means the image is inverted and magnified by a factor of 2, located at a distance of 20 cm on the same side as the object from the mirror.