How do you find the area of an isosceles triangle with 2 equal sides and 1 angle?
It really depends on the angle. If the angle is at the point where the two equal sides intersect then you can divide the triangle into two equal parts (forming a right angle with the base), divide the angle by two, then use the following equation(side*arccos(your angle/2))*((side*arcsin(your angle/2)))if the angle is not where the two equal sides intersect then you can divide the triangle into two equal parts (from the point where the two equal sides intersect down to a right angle with the base) then use the following equation.(side*arcsin(your angle)*(side*arccos(your angle))