5555
There are only five distinct odd digits.
There are 320 such numbers.
To find the number of odd numbers between 1000 and 9999 with distinct digits, we first note that the last digit must be one of the odd digits: 1, 3, 5, 7, or 9. This gives us 5 options for the last digit. For the first digit (thousands place), we can choose from 1 to 9 (excluding the last digit), giving us 8 options. The second digit (hundreds place) can be any digit from 0 to 9, excluding the first and last digits, which gives us 8 options. Finally, the third digit (tens place) can be any digit from 0 to 9, excluding the first, last, and second digits, yielding 7 options. Thus, the total count is: 5 (last digit) × 8 (first digit) × 8 (second digit) × 7 (third digit) = 2240. Therefore, there are 2240 odd numbers between 1000 and 9999 with distinct digits.
999999 is six digits and odd.
987,653
There are only five distinct odd digits.
There are 320 such numbers.
To find the number of odd numbers between 1000 and 9999 with distinct digits, we first note that the last digit must be one of the odd digits: 1, 3, 5, 7, or 9. This gives us 5 options for the last digit. For the first digit (thousands place), we can choose from 1 to 9 (excluding the last digit), giving us 8 options. The second digit (hundreds place) can be any digit from 0 to 9, excluding the first and last digits, which gives us 8 options. Finally, the third digit (tens place) can be any digit from 0 to 9, excluding the first, last, and second digits, yielding 7 options. Thus, the total count is: 5 (last digit) × 8 (first digit) × 8 (second digit) × 7 (third digit) = 2240. Therefore, there are 2240 odd numbers between 1000 and 9999 with distinct digits.
999999 is six digits and odd.
There are 5760 such numbers.
987,653
that question cant be answered unless it was 3 odd-digits or 4 odd-digits with 1 even digit i think.
874
450.
The smallest 12-digit odd number is 1,000,000,000,001. This number has 12 digits, starts with a 1, and ends with a 1, making it odd. All other 12-digit numbers either have fewer digits or are even.
To form a two-digit odd number using the digits 123456789 without repetition, the unit's digit must be an odd number. The available odd digits are 1, 3, 5, 7, and 9, giving us 5 options for the unit's place. For the ten's place, we can choose any of the remaining 8 digits. Therefore, the total number of two-digit odd numbers is (5 \times 8 = 40).
99999. And if all the digits need to be different, it is 98765.