A 4-digit number divisible by both 5 and 9 must be divisible by their least common multiple, which is 45. To find a 4-digit number divisible by 45, we need to find a number that ends in 0 and is divisible by 45. The smallest 4-digit number that fits these criteria is 1005 (45 x 22 = 990, and adding 15 gives us 1005).
45,000 / 5 = 9,000 45,000 / 9 = 5,000
144 is divisible by 12 and 9.
900000
No. Nine is not evenly divisible by five.
Nine-hundred ninety-eight. 998. It's divisible by two, so it's even, and a three digit number.
45,000 / 5 = 9,000 45,000 / 9 = 5,000
144 is divisible by 12 and 9.
144
108
900000
987652431
Numbers that are co-prime won't both be divisible by nine.
Yes, it is. One way to tell if a number is divisible by nine is to add up all of the numbers until you get a one digit number, and if the number isn't nine, the number isn't divisible by nine. 4+8+6+0= 18 1+8=9
This is a weekly question posted by Columbus State University. See http://www.colstate.edu/mathcontest/problem.php?CategoryID=3&LinkID=CurrentPlease do not answer this question as this person is too lazy to figure it out themselves.
There are many possible solutions. One such is 132486970
The trick to this question is to realize that you can tell a number is divisible by nine by observing whether the sum of it's digits is divisible by nine.For example, we know that the number 25731 is divisible by nine, because 2 + 5 + 7 + 3 + 1 = 18, and 18 is divisible by nine.So in this case, what we want is a value for "A" in which 3 + A + A + 1, or 2A + 4, is divisible by 9. "A" also has to be less than ten (as we're dealing with a specific digit). That leaves us with only one possible digit, 7. 3 + 7, + 7 + 1 = 18, and 18 is indeed divisible by nine, so we know that 3771 is also divisible by nine.
No. Nine is not evenly divisible by five.