You use trigonometry. If the triangle is a right triangle, then you can use the Pythagorean theorem (a2 + b2 = c2 where c is the hypotenuse). This requires you to know two of the sides of the triangle. You can also use the relationship: sin A = a/c cos A = b/c tan A = a/b where "A" is a non-right angle of a right triangle, "a" is the length of the side opposite of the angle "A", "b" is the length of the side adjacent to the angle "A" and "c" is the length of the hypotenuse. If the triangle is NOT a right triangle, you can use the law of sines or the law of cosines. The law of sines: a /sin A = b / sin B = c / sin C where "a" is the side opposite of angle "A", "b" is the side opposite of angle "B" and "c" is the side opposite of angle "C". The law of cosines: a2 = b2 + c2 - b*c*cos A b2 = a2 + c2 - a*c*cos B c2 = a2 + b2 - a*b*cos C where "c" is the hypotenuse, "a" and "b" are the other sides of the triangle and "C" is the angle opposite of "c", "B" is the angle opposite of "b" and "A" is the angle opposite of "a".
A squared + b squared = c squared For a right triangle A b c side lengths For a and b legs of the triangle C hypotenuse of triangle which is the side opposite the right angle
Use the Hero's formula: Let s = (a + b + c)/2. Then the area of the triangle equals√[s(s - a)(s - b)(s - c)], where a, b, and c denote the sides of the triangle.
Area of triangle=√(s-a)(s-b)(s-c)
The pythagorean theorem is only used for a right triangle. Formula: a^2+b^2=c^2 the "a" and "b" represent the legs of the triangle and the "c" represents the hypotenuse.
Let the angles be a, b and c There are 180 degrees in a triangle: 180-(a+b) = c 180-(a+c) = b 180-(b+c) = a
No. An equiangular triangle is always equilateral. This can be proven by the Law of Sines, which states that sin A / a = sin B / b = sin C / c, where A, B and C are angles of a triangle and a, b and c are the opposing sides of their corresponding angles. If A = B = C, then sin A = sin B = sin C. Therefore for the equation to work out, a = b = c. Therefore the eqiangular triangle is equilateral, and therefore not scalene, which requires that all sides of the triangle be of different lengths.
In a right the triangle with legs a, b and hypotenuse c, a^2 = c^2 - b^2 or b^2 = c^2 - a^2.
If the lengths of the sides are a, b, and c then it is (a + b + c)/2.
You use trigonometry. If the triangle is a right triangle, then you can use the Pythagorean theorem (a2 + b2 = c2 where c is the hypotenuse). This requires you to know two of the sides of the triangle. You can also use the relationship: sin A = a/c cos A = b/c tan A = a/b where "A" is a non-right angle of a right triangle, "a" is the length of the side opposite of the angle "A", "b" is the length of the side adjacent to the angle "A" and "c" is the length of the hypotenuse. If the triangle is NOT a right triangle, you can use the law of sines or the law of cosines. The law of sines: a /sin A = b / sin B = c / sin C where "a" is the side opposite of angle "A", "b" is the side opposite of angle "B" and "c" is the side opposite of angle "C". The law of cosines: a2 = b2 + c2 - b*c*cos A b2 = a2 + c2 - a*c*cos B c2 = a2 + b2 - a*b*cos C where "c" is the hypotenuse, "a" and "b" are the other sides of the triangle and "C" is the angle opposite of "c", "B" is the angle opposite of "b" and "A" is the angle opposite of "a".
A squared + b squared = c squared For a right triangle A b c side lengths For a and b legs of the triangle C hypotenuse of triangle which is the side opposite the right angle
#include<stdio.h> #include<conio.h> void main() { int a,b,c; clrscr(); printf("\n Enter the 3 sides of Triangle: "); scanf("%d %d %d",&a,&b,&c); printf("\nYour entered side is a=%d b=%d c=%d",a,b,c); if(a==b && b==c && a==c) { printf("\n EQUILATERAL TRIANGLE.");//All sides equal in case of Equilateral triangle } else if(a!=b&&b!=c) printf("\n SCALENE TRIANGLE."); //All sides unequal else printf("\n ISOCELES TRIANGLE."); //At least 2 sides equal getch(); }
a + b + c
A, B, then C
a^2 + b^2 = c^2 a and b are the distances for the side of the triangle and c is the hypotenuse(long side)
you add the sides together . a /\b a+b+c /_\ c
Use Pythagorean theorem if you have a right triangle with legs a and b and hypotenuse c. a^2+b^2=c^2 a=sqrt(c^2-b^2) it is possible to find b and c in a similar way.