The solution to this problem was discovered by Gauss when he realized that if you write the numbers 1, 2, 3, ... down a column until you reach the midway point, and then start writing the remaining ones up the next column, that each row was the exact same sum.
The equation for the sum of the integers 1 to n is 1/2(n)(n+1).
The sum of the integers from 1 through 300 is 44,850.
No. The sum of all integers between 1 and 500 is 124,749.
101
The sum of the first 201 positive integers is 20100 if you include 0 (i.e. from 0 to 200). If you sum the integers from 1 to 201 instead, the sum is 20301.
The integers are -1, 1 and 3.
The sum of the integers from 1 to 100 inclusive is 5,050.
The sum of integers from 1 to 2008 = 2008*2009/2 = 2017063
The sum of all integers from 1 to 20 inclusive is 210.
The sum of the integers from 1 through 300 is 44,850.
The sum of the integers 1 to 99 is 4950. An easy way to figure this out is using the equation N*(N+1)/2 where N is the largest number in the set.
No. The sum of all integers between 1 and 500 is 124,749.
101
(300 x (300 + 1)) / 2 = 45150 Therefore, the sum of all the integers from 1 to 300 is 45150.
The sum of the first 201 positive integers is 20100 if you include 0 (i.e. from 0 to 200). If you sum the integers from 1 to 201 instead, the sum is 20301.
The first odd positive integers are "1" and "3" which the sum is 4.
55
To calculate the sum of the numbers 1 to n, the formula is: sum = n(1 + n) / 2 So, an equation to find the sum of the integers 1 to 2010 is: sum = 2010 x (1 + 2010) / 2