The solution to this problem was discovered by Gauss when he realized that if you write the numbers 1, 2, 3, ... down a column until you reach the midway point, and then start writing the remaining ones up the next column, that each row was the exact same sum.
The equation for the sum of the integers 1 to n is 1/2(n)(n+1).
The sum of the integers from 1 through 300 is 44,850.
No. The sum of all integers between 1 and 500 is 124,749.
101
The sum of the first 201 positive integers is 20100 if you include 0 (i.e. from 0 to 200). If you sum the integers from 1 to 201 instead, the sum is 20301.
The integers are -1, 1 and 3.
The sum of integers from 1 to 2008 = 2008*2009/2 = 2017063
The sum of the integers 1 to 99 is 4950. An easy way to figure this out is using the equation N*(N+1)/2 where N is the largest number in the set.
(300 x (300 + 1)) / 2 = 45150 Therefore, the sum of all the integers from 1 to 300 is 45150.
55
15150
The sum of all the the integers between 1 and 2008 (2 through 2,007) is 2,017,036.
-1, -3 and -8
Sum of first n integers is n/2 times n + 1 ie 27.5 x 56 which is 1540
Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
20,100
The question makes no sense.. you can easily find the sum of integers between 1 and 300 but what does 11 or 13 have to do with it.
The integers are -2, -1, 0 and 1.