A five-digit number that is divisible by both 5 and 9 must be divisible by their least common multiple, which is 45. To find a five-digit number divisible by 45, we can start with the smallest five-digit multiple of 45, which is 10005. The next number divisible by 45 would be 10005 + 45 = 10050. Therefore, 10050 is a five-digit number that is divisible by both 5 and 9.
to be divisible by 5 the last digit of the number has to be 0 or 5
15000
If the units digit is a five or a zero, then the number may be evenly divided by five. (Zero itself exempted.)
You know a number is divisible by five when its last digit has either a 5 or 0.
45,000 / 5 = 9,000 45,000 / 9 = 5,000
There are 180 3-digit numbers divisible by five.
to be divisible by 5 the last digit of the number has to be 0 or 5
11,115
15000
99045
12 345
The highest six-digit number divisible by 3, 4, and 5 is 999960.
Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.
If the units digit is a five or a zero, then the number may be evenly divided by five. (Zero itself exempted.)
123456
You know a number is divisible by five when its last digit has either a 5 or 0.
45,000 / 5 = 9,000 45,000 / 9 = 5,000