It is (3*sqrt(3)*s^2)/2 square units where the length of a side is s units long.
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(3x2 √3) / 2 Where x is the length of a side, given that the hexagon is a regular hexagon. However, if the hexagon is is not regular, you will have to find the area of the two trapeziums within the hexagon, find the area of them, and add them together.
If it is a regular hexagon then make 6 triangles then find the area of one then multiply by 6.
First we assume it is a regular hexagon meaning all the angles are the same and the sides are the same length. Recalling that a regular hexagon can be broken up into 6 triangles, we find the area of the hexagon by finding the area of one triangle and multiply by six. (recall the area of triangle is Height x 1/2 Base ) You can also find the area of a hexagon using the formula Area==ap/2 where a is the apothem and p is the perimeter. But that just gives you the area of the 2 dimensional base, not the volume. To calculate the volume, multiply the area found above by the height of the hexagonal container.
s = 8 and a = 1.3 are not compatible for a regular hexagon.
There is no standard formula. It is necessary to partition the irregular hexagon into more convenient shapes such as triangles and quadrilaterals, find their areas and sum the results.