Equation of the straight line: y = -3/5x+2 in slope intercept form
-1
4/5
2
-1
-1
-1
-1
4/5
2
-1
-1
Points: (-1, 8) and (5, -4) and the slope works out as -2
3/5
slope=-8,1
To find the slope of the line that contains the points (4, -1) and (-1, 4), use the slope formula: ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the points, we have ( m = \frac{4 - (-1)}{-1 - 4} = \frac{4 + 1}{-5} = \frac{5}{-5} = -1 ). Therefore, the slope of the line is -1.
Answer this question… What is the slope of the line that contains the points (-5, 3) and (2, 3)?
2